Logan Wants To Mix An 18% Acid Solution With A 45% Acid Solution To Get 16 L Of A 36% Acid Solution. How Many Liters Of The 18% Solution And How Many

Logan wants to mix an 18% acid solution with a 45% acid solution to get 16 L of a 36% acid solution. How many liters of the 18% solution and how many liters of the 45% solution should be mixed?

 

Answer:

v1 = 5.3333 L

v2 = 10.6667 L

Step-by-step explanation:

Given: let c =concentration

                 v =volume

           c1 = 18% = 0.18

           c2 = 45% = 0.45

            c3 = 36% = .36

             v3 = 16 L

Required: v1 and v2

v1 + v2 = 16 (eq 1)

(c1)(v1) + (c2)(v2) = (c3)(v3)

0.18(v1) + 0.45(v2) = 16(0.36)

0.18(v1) + 0.45(v2) = 5.76 (eq 2)

solve v1 and v2 using q 1 and eq 2

v1 = 16/3 L = 5.3333 L

v2 = 32/3 L = 10.6667 L